10x^2=1.6

Solution for 10x^2=1.6 equation:

10x^2=1.6

We move all terms to the left:

10x^2-(1.6)=0

We add all the numbers together, and all the variables

10x^2-1.6=0

a = 10; b = 0; c = -1.6;
Δ = b2-4ac
Δ = 02-4·10·(-1.6)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*10}=\frac{-8}{20}
=-2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*10}=\frac{8}{20}
=2/5
$